How many grams of co2 would be
require passed through
lime water to produce
of caCoz- [ca=40, C. 12,0=16)
Answers
Answered by
1
Answer:
Explanation:
Chemical reaction involved is:
CaCO
3
→CaO+CO
2
Molar mass of CaCO
3
=40+12+16×3=100 g
According to the balanced reaction 100 g of CaCO
3
produces 1 mol of CO
2
i.e. 22.4 L at STP.
∴50 g CaCO
3
will produce
100
22.4
×50=11.2 L CO
2
at STP.
Hope it helps
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Answered by
1
Answer:
answer
Explanation:
ANSWER
Chemical reaction involved is:
CaCO
3
→CaO+CO
2
Molar mass of CaCO
3
=40+12+16×3=100 g
According to the balanced reaction 100 g of CaCO
3
produces 1 mol of CO
2
i.e. 22.4 L at STP.
∴50 g CaCO
3
will produce
100
22.4
×50=11.2 L CO
2
at STP.
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