How many grams of concentrated nitric acid solution should be used to prepare 250mL of 2M HNO3?the concentrated acid is 70%(w/w) HNO3
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Heya
Step1: Apply the molarity formula to calculate the moles of HNO3.
HNO3 moles = 2M x .250 L = 0.50 moles.
Step2: Convert the moles of HNO3 into mass.
Mass = moles x molar mass = 0.50 moles x 63.01g/mole = 31.5 g HNO3.
Thus, 31.5 g HNO3 will be present in 100g x 31.5 g HNO3/70g = 45g solution
Hope it helped ya.
Step1: Apply the molarity formula to calculate the moles of HNO3.
HNO3 moles = 2M x .250 L = 0.50 moles.
Step2: Convert the moles of HNO3 into mass.
Mass = moles x molar mass = 0.50 moles x 63.01g/mole = 31.5 g HNO3.
Thus, 31.5 g HNO3 will be present in 100g x 31.5 g HNO3/70g = 45g solution
Hope it helped ya.
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