How many grams of concentrated nitric acid solution should be used to prepare 250 ml of 2.0 m hno3? The concentrated acid is 70% hno3?
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The number of moles of nitric acid can be obtained by multiplying the molarity with volume
M×V=Moles of H in HNO3=
1000/250×2=0.5
The mass of nitric acid can be obtained by multiplying the number of mols with molar mass and dividing with percentage concentration.
∴HNO3 required =0.5×63×70/100=45g
Thus 45.0 g conc. HNO3
of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3
.
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