How many grams of concentrated nitric acid solution should be used to prepare 250 ml
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As we know,no of moles=M* VSo,req no of moles=(250/1000)*2=0.5And,req mass of HNO3=0.5*63=31.5Now 70g of HNO3 present in 100g of solSo 1g of HNO3 present in 100/70g of solHence,Req amount of HNO3 =(100/70)*31.5=45g
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