how many grams of cu are deposited. by 900C of charges
Answers
Answer:
A solution of CuSO4 is electrolysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?
t = 600 s
Charge = current x time
= 1.5 A x 600s = 900 C
According to the reaction : Cu2+(aq) + 2e– → Cu(s)
We require 2F or 2 x 96487 C to deposit 1 mol or 63 g of Cu
For 900 C, the mass of Cu deposited = ( 63g mol − 1 × 900C )2 × 96487C
mol − 1 = 0.2938g.(63 g mol-1 × 900 C)2 × 96487 C mol-1 = 0.2938 g.
Answer:
A solution of CuSO4 is electrolysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?
t = 600 s
Charge = current x time
= 1.5 A x 600s = 900 C
According to the reaction : Cu2+(aq) + 2e– → Cu(s)
We require 2F or 2 x 96487 C to deposit 1 mol or 63 g of Cu
For 900 C, the mass of Cu deposited = ( 63g mol − 1 × 900C )2 × 96487C
mol − 1 = 0.2938g.(63 g mol-1 × 900 C)2 × 96487 C mol-1 = 0.2938.g