How many grams of CuSO4.5H2O are necessary in order to prepare 325g 4 w/w% CuSO4 solution ( by mass )?
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Answer:
The molecular weight of water H
2
O=2(1)+16=18.
When 1 mole of CuSO
4
⋅5H
2
O is heated, 5 moles of water are lost.
The molecular weight of CuSO
4
⋅5H
2
O=64+32+4(16)+5(18)=250 g/mol
Mass of water lost =5(18)=90 g
Percentage loss of mass of CuSO
4
⋅5H
2
O=
250
90
×100=36 %.
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