Question

How many grams of dibasic acid (molecular mass 200) should be present in 100 ml of the aqueous solution to give 0.1 N solution

Answer 1

Answer:

Explanation:

quivalent wt. of dibasic acid = mol. wt/2 = 200/2 = 100 Strength = 0.1 N, m = ? , V = 100 mL then, m = EVN/1000 = (100 x 100 x 0.1)/1000 = answered this

Equivalent weight of solute = 200/2=100 N= wt. of solute in grams*1000/Equivalent wt. Of solute *volume (ml) 0.1 =wt. Of solute in grams *1000/100*100 Wt. Of solute in grams =0.1*100*100/1000