Question

how many grams of dihydrogen (h2) are required to react completely with 490g dinitrogen to form ammonia(atomic mass of h2=1,N=14)​

Answer 1

Explanation:

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Answer 2

The reaction is as follows:

 N2 + 3H2--------->2NH3

R.M.M of NH3 is 14+3X1=>17 g mol-1

Hence, 1 mol of NH3 has mass of 17g.

Hence, 490 g of NH3 is 490/17=> 28.82 mol

Hence 2 parts of NH3 is 28.82 mol

1 part of NH3=28.82/2=> 14.41 mol

Hence 3 X 14.41 mol of Hydrogen gas is required, =>43.23 mol

As molar mass of H2=2 g mol-1.

Hence, the mass of Dihydrogen required will be 2 X 43.23=> 86.46 g of Dihydrogen.