Question

How many grams of do basic acid (mol wt = 200) should be present in 100 ml of the aqueous
solution to give 1 Normal?​

Answer 1

Answer:

1 g

Explanation:

Molarity of dibasic acid

M=

200

ω

×

100

1000

N=M×2→ dibasic acid

10

1

=

200

ω

×

100

1000

×2

ω=

1000

1000

ω=1gm

So , correct answer is 1g