how many grams of ethylene can be burnt completely by oxygen gas produced from the complete decomposition of 49 gm of kclo3
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Answer:
Explanation:
2KClO
3
→
2KCl
+
3O
2
This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.
Using simple proportion:
2
mol
→
3
mol
∴
1
mol
→
3
2
mol
The
M
r
of
O
2
=
32
∴
mass O
2
=
32
×
3
2
=
48
g
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