How many grams of H2SO4 acid will be required
for completely dissolving 6 gram MgCO3.
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Answer:
Molar mass of MgCO3 is =84.3g
∴ 3g of MgCO3=3/84.3mol=0.036mol
The balanced equation is:
H2SO4+MgCO3→MgSO4+H2CO3
It is evident that one mole of sulphuric acid is required to dissolve i mole MgCO3
∴ 0.036 mole of sulphuric acid is required to dissolve 0.036 mole of MgCO3
or
0.036×98.1=35.5g of sulphuric acid is required.
Explanation:
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