Question

How many grams of h2so4 are contained in 0.05 lt of 0.5 solution?

Answer 1

Answer:

3.25g

Explanation:

1 mol of H2SO4 = 130g

(0.5 mol/L)(0.05 L ) of H2SO4 = x g

by unitary method x=3.25g

Answer 2

Answer:

2.45 gm of sulphuric acid is contained in 0.05L of a solution.

Explanation:

1 mole of H2SO4 will equal to 98.079 gm/mol.

Therefore 0.5M of H2SO4 will have- 98.079gm/mol x 0.5M = 49.0395 gm/L

In the question they have asked for the mass of 0.05L so it should be multiplied as-

Molar mass/L x molarity of a given solution x volume of solution (L)

98.079 x 0.5 x 0.05 = 2.45 gm.

Therefore 2.45 gm of sulphuric acid contained in 0.05L of a solution.