Question

how many grams of h2so4 are needed to completly dissolve 3g mgco3.​

Answer 1

Answer:

Dont known bro .......

Answer 2

Molar mass of MgCO
3
​
is =84.3g
∴ 3g of MgCO
3
​
=3/84.3mol=0.036mol
The balanced equation is:
H
2
​
SO
4
​
+MgCO
3
​
→MgSO
4
​
+H
2
​
CO
3
​

It is evident that one mole of sulphuric acid is required to dissolve i mole MgCO
3
​

∴ 0.036 mole of sulphuric acid is required to dissolve 0.036 mole of MgCO
3
​

or
0.036×98.1=35.5g of sulphuric acid is required.