how many grams of h2so4 are needed to completly dissolve 3g mgco3.
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Answered by
1
Molar mass of MgCO
3
is =84.3g
∴ 3g of MgCO
3
=3/84.3mol=0.036mol
The balanced equation is:
H
2
SO
4
+MgCO
3
→MgSO
4
+H
2
CO
3
It is evident that one mole of sulphuric acid is required to dissolve i mole MgCO
3
∴ 0.036 mole of sulphuric acid is required to dissolve 0.036 mole of MgCO
3
or
0.036×98.1=35.5g of sulphuric acid is required.
3
is =84.3g
∴ 3g of MgCO
3
=3/84.3mol=0.036mol
The balanced equation is:
H
2
SO
4
+MgCO
3
→MgSO
4
+H
2
CO
3
It is evident that one mole of sulphuric acid is required to dissolve i mole MgCO
3
∴ 0.036 mole of sulphuric acid is required to dissolve 0.036 mole of MgCO
3
or
0.036×98.1=35.5g of sulphuric acid is required.
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