How many grams of h2so4 are present in 0.25 mole of h2so4
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Answer:
14.5grams(mark this answer as brainliest)
Explanation:
Molar mass of H2SO4=
Molar mass of H(x2)+Molar mass of Sulphur(x1)+ Molar mass of Oxygen(x4).
This gives us,
[(1*2)+(32*1)+(16*4)]g/mol
=> [2+32+64]g/mol
=> 98g/mol.
Therefore 1mole of H2SO4 = 98grams
0.25(1/4)mole ⇒1/4 * 98
0.25mole ⇒14.5grams
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