Question

how many grams of h3po4 is required to comletely neutralize 120g of naoh

Answer 1

Answer:

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How many grams of h3po4 is required to comletely neutralize 120g of Naoh?

${\tt{\red{\underline{\underline{\huge{Answer}}}}}}$

120 g of NaOH (molar mass 40 g/mol) = 120g/40g/mol

=3moles

3NaOH+H3PO4→Na3PO4+3H2O

3 moles of NaOH will react with 1 mole of H3PO4.

Molar mass of H3PO4

= 98 g/mol.

Mass of H3PO4

=1mol×98g/mol=98mol (Answer)

Explanation:

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