How many grams of HNO3 are required to prepare 500 mL of a 0.601 M HNO3 solution?
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The right answer is 18.93 grams.
Since, the equivalent weight of nitric acid is 63 grams,
1L HNO3 solution of 1M contains 63 grams
.5L HNO3 solution of 0.601M contains 63×0.601×0.5=18.93grams
Since, the equivalent weight of nitric acid is 63 grams,
1L HNO3 solution of 1M contains 63 grams
.5L HNO3 solution of 0.601M contains 63×0.601×0.5=18.93grams
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