Question

How many grams of i2 are present in a solution which requires 40 ml of 0.11 n?

Answer 1

Answer:

Milli equation of $I_{2}$= Milli equation of $Na_{2} S_{2} O_{3}$

$\frac{W}{254/2} *1000=40*0.11$

weight of $I_{2} =0.588g$