Question

How many grams of iodine. Are present in a solution which require 40 ml of 0.11?

Answer 1

Explanation:

Iodine will be S2O32– + I2 → S4O62– + 2I–.

Hope this helps you.

Answer 2

Answer:

The Questions and Answers of How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'.