How many grams of iodine. Are present in a solution which require 40 ml of 0.11?
Answers
Answered by
0
Explanation:
Iodine will be S2O32– + I2 → S4O62– + 2I–.
Hope this helps you.
Answered by
1
Answer:
The Questions and Answers of How many gm of I2 are present in a solution which requires 40 ml of 0.11N Na2S2O3 to react with it via the reaction : S2O32– + I2 → S4O62– + 2I– ?a)12.7gb)0.558gc)25.4gd)11.4gCorrect answer is option 'B'.
Similar questions