Question

How many grams of iron are needed to combine with 25.6g of O to make Fe2O3?

Answer 1

Answer:- 59.6 g of Iron.

Solution:- The balanced equation is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

From this equation, there is 4:3 mol ratio between Fe and oxygen.

So, first of all we convert the grams of oxygen to moles and then multiply these moles by the mol ratio to get the moles of Iron used. Further, these moles are converted to grams on multiplying by atomic mass of Iron.

Molar mass of oxygen is 32 gram per mol and it will be used to convert its grams to moles.

The calculations are shown below by using dimensional analysis:

$25.6gO_2(\frac{1molO_2}{32gO_2})(\frac{4molFe}{3molO_2})(\frac{55.845gFe}{1molFe})$

= 59.6 g Fe

So, 59.6 grams of Iron are needed to combine with 25.6 grams of oxygen.

Answer 2

Answer: 59.6g Fe

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