Question

How many grams of JUL is present in 150ml of .52 M HCL solution​

Answer 1

Molar mass of HCl = 36.5 g

Molarity = 0.52 M

Volume of solution = 150 mL

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Molarity = Given mass of HCl×1000Molar mass of HCl×Volume of solution 0.52 = Given mass of HCl×100036.5×1502.84 g