Question

How many grams of KCIO: must be decomposed to prepare 3.36 litres of oxygen at STP?(At mass of K=39u, Cl=35.5u, O=16u)​

Answer 1

Required Answer:

☑ Refer To The Attachment!

Answer 2

Answer:

2KClO3--- KCl + 3O2

247g 3x22.4L

according to this equation,,

247g of KClO3 decompose to form 3x22.4L = 67.2L of O2 at STP

this means,,

67.2L of O2 is formed by KClO3 = 247g

3.36g of O2 will be formed by KClO3 = 247x3.36/67.2 =12.35g