Question

How many grams of kcl are heated to get 17L of oxygen in proof?​

Answer 1

Answer:

1.96g

O

2

Explanation:

We first need our balanced equation:

2

K

C

l

O

3

→

2

K

C

l

+

3

O

2

Now apply stoichiometry, and you result with this:

5.00

g 2KClO3

⋅

1mol 2KClO3

122.55g 2KClO3

⋅

3mol O2

2mol 2KClO3

⋅

16.00g O2

1mol O2

=

1.96g O2