How many grams of Kcl are heated to get 17L of oxygen in proof?
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Explanation:
At NTP, 11.2 L of oxygen corresponds to 22.411.2=0.5mol
2KClO3heat2KCl+3O2
Thus, 2 moles of potassium chlorate on heating gives 3 moles of oxygen.
Thus, 32×0.5=31 moles of potassium chlorate on heating gives 11.2 L of oxygen at NTP.
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