Question

how many grams of KCL must be added to 75 gram of water to produce a solution that is 2.25 molal​

Answer 1

Answer:12.87 grams.

Explanation:

Molality is defined asnumber of moles of solute dissolved in 1000 grams of solvent.

Answer 2

Hello Dear,

● Answer -

W2 = 12.57 g

◆ Explanation -

# Given -

W1 = 75 g = 0.075 kg

M1 = 18 g/mol

W2 = ?

M2 = 74.5 g/mol

m = 2.25 mol

# Solution -

Molality of solution is calculated by -

Molality = moles of solute / mass of solvent

m = n2 / W1

m = (W2/M2) / W1

W2 = m × M2 × W1

W2 = 2.25 × 74.5 × 0.075

W2 = 12.57 g

Therefore, 12.57 g of KCl must be added to 75 gram of water to produce a solution that is 2.25 molal.

Hope this helps you.