Question

how many grams of kcl must be added to 75g of water to produce a solution with a molality 2.25

Answer 1

Answer:

12.57 g of KCl

Explanation:

molality = weight of KCl × 1000

/ molar mass of KCl × 75 g

H2O

= x × 1000/74.5×75 = 2.25

so, X = 12.57

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Answer 2

Answer:

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● Answer -

W2 = 12.57 g

Explanation:

Given to us that-

W1 = 75 g = 0.075 kg

M1 = 18 g/mol

W2 = ?

M2 = 74.5 g/mol

m = 2.25 mol

# Solution -

Molality of solution is calculated by -

Molality = moles of solute / mass of solvent

m = n2 / W1

m = (W2/M2) / W1

W2 = m × M2 × W1

W2 = 2.25 × 74.5 × 0.075

W2 = 12.57 g

Therefore, 12.57 g of KCl must be added to 75 gram of water to produce a solution that is 2.25 molal.