Question

How many grams of LiOH are needed to make 100 ml of a 0.1 M solution?

Answer 1

Explanation:

0.24 grams of LiOH is required

The molarity of LiOH is 0.1M

The given volume

M = W1 × 1000

------------------

m1 × V(ml)

m1 = molecular mass of LiOH = 24

putting the values in the equation

0.1 = W1 × 1000

-------------------

24 × 100

W1 = 0.1 × 24 ×100

-----------------------

1000

0.24 grams of LiOH is required

Answer 2

$\huge\underline\green{\sf Answer}$

$\large{\boxed{\sf weight\:of\:LiOH(w)=2g}}$

$\huge\underline\green{\sf Solution}$

Given :-

Volume = 100 ml

Molarity (M) = 0.1M

Molecular weight of LiOH $\sf{M_{wt}}$=>7+16+1= 24

w = ?

Formula here we use is :-

$\large\boxed{\sf Molarity={\frac{weight\:of\:Solute \times 1000}{M_{wt} \times Volume}}}$

On putting value :-

$\large{\sf 0.1 ={\frac{{w} \times 1000}{24 \times 100}}}$

$\large{\sf w={\frac{1 \times 24}{10 \times 10}}}$

$\huge\red{\boxed{\sf w = 0.24 g}}$