How many grams of Magnesium Sulphate are present in 135g of solid left by evaporation of sea water?
Answers
Answered by
163
we have to find the amount of Magnesium sulphate present in 135g of solid left evaporation of sea water.
solution : you forgot to attach the table that shows the mass of various compound when 1 litre of sea water is evaporated.
from table attached in answer,
it is clear that 6g of Magnesium sulphate present in 45g of salt gotten by evaporating of 1 litre of sea water.
∵ 6 g of Magnesium sulphate present in 45g of salt.
∴ magnesium sulphate present in 135g of salt = 6 × 135/45 = 18 g
therefore the 18g of Magnesium sulphate present in 135g of solid left by evaporation of sea water.
Attachments:
Answered by
17
18 g is the answer..,..
Hope it help you...
Similar questions