Chemistry, asked by tharun2628, 1 day ago

How many grams of Magnesium Sulphate are present in 135g of solid left by evaporation of sea water?​

Answers

Answered by abhi178
163

we have to find the amount of Magnesium sulphate present in 135g of solid left evaporation of sea water.

solution : you forgot to attach the table that shows the mass of various compound when 1 litre of sea water is evaporated.

from table attached in answer,

it is clear that 6g of Magnesium sulphate present in 45g of salt gotten by evaporating of 1 litre of sea water.

∵ 6 g of Magnesium sulphate present in 45g of salt.

∴ magnesium sulphate present in 135g of salt = 6 × 135/45 = 18 g

therefore the 18g of Magnesium sulphate present in 135g of solid left by evaporation of sea water.

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Answered by ssahil9999992
17

18 g is the answer..,..

Hope it help you...

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