Chemistry, asked by bhaktipatel3043, 9 months ago

How many grams of magnesium would contain the same number of atoms as 26.982 g of Al

Answers

Answered by areonbanerjee361

0

Answer:

24 g approx

Explanation:

1 mole of Al = 26.982g = 6× 10^23 atoms

hence 1 mole of Mg will also contain 6×10^23(avagadro no.) no. of atoms

1 mole of Mg = 24.31 g ( or 24 g)

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