how many grams of mass decrease is observed when 1 mole of gypsum is carefully converted into 1 mole of plaster of Paris
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Answers is 27 Gram....
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Given:
No of moles of gypsum = 1 mole
No of moles of Plaster of Paris = 1 mole
To Find:
The decrease in mass when this conversion takes place.
Calculation:
- The formula of gypsum is CaSO4.2H2O.
- The formula of Plaster of Paris is CaSO4.1/2H2O.
- The conversion takes place as follows:
CaSO4.2H2O + Heat → CaSO4.1/2H2O + 3/2 H2O
- So, 3/2 moles of water leaves from it.
- The molar mass of water = 18 gm
⇒ Mass of 3/2 moles = 18 × 3/2 = 27 gm
- So, 27 grams of mass decrease is observed on converting 1 mole of gypsum into 1 mole of Plaster of Paris.
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