How many grams of mg will react with HCl to form 112ml of H2 gas at Stp
Answers
Answer:
0.06 g of
M
g
will dissolve.
112 ml of
H
2
at STP will be produced.
Explanation:
First We will consider the equation of reaction of HCl with Mg.
M
g
+
2
H
C
l
→
M
g
C
l
2
+
H
2
That means, 1 mol of
M
g
reacts with 2 mol of
H
C
l
to produce 1 mol of
M
g
C
l
2
and 1 mol
H
2
.
The solution contains 1 mol
H
C
l
in 1
d
m
3
. or, the strength of the solution is 1
m
o
l
L
−
1
So, Amount of
H
C
l
in 10
c
m
3
or 10
m
l
= 0.01 mol
That means, there is only 0.01 mol
H
C
l
for reaction.
So,
0.01
2
mol = 0.005 mol Mg will dissolve in the solution and produce 0.005 mol of
H
2
too. [Observe the mole ratio]
0.005
mol Mg =
12
⋅
0.005
g =
0.06
g
Before finding the volume of hydrogen, Let's assume the gas is at STP.
1 mol of any gas takes volume of 22.4 L at STP
0.005 mol of any gas will take volume of
22.4
⋅
0.005
L at STP
= 0.112 L at STP
= 112 ml
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Answer:
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