Question

How many grams of mgco3 dissolved per litre gives 84 ppm hardness?

Answer 1

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Answer 2

Answer : The mass of $MgCO_3$ is, 71 mg/L

Solution : Given,

Molar mass of $MgCO_3$ = 84 g/mole

Hardness = 84 ppm

Formula used :

$\text{Hardness}=\text{mg/L of }MgCO_3\times \frac{100}{\text{Molar mass of }MgCO_3}$

Now put all the given values in this formula, we get

$84ppm=\text{ppm of }MgCO_3\times \frac{100}{84}$

$\text{ppm of }MgCO_3=70.56=71ppm=71mg/L$

Therefore, the mass of $MgCO_3$ is, 71 mg/L