How many grams of N2 is required to obtain 1000 litre of ammonia at STP
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Reaction : N2 + 3 H2 ----> 2NH3
So moles of N2 = moles of NH3
M/28 = 1000/ 22.4
Where 28 is molar mass of N2 and 22.4 is volume of gas at STP
Solve the equation and get M
Thanks
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