Question

How many grams of Na2CO3 should be dissolved in 250 g of water to prepare 0.1 m solution

Answer 1

Okay, so here is how you do it

First, you find the moles of sodium carbonate in the given solution.

moles=concentraton x volume (n=cv)

=0.1mol/dm3 x (250/1000)dm3

(0.1M = 0.1mol/dm3 and converting 250ml into dm3 by dividing by 1000)

=0.025mol

Next, you find out the molecular mass of Na2CO3=

( 23 x 2) + 12 + (16 x 3)

= 46 + 12 + 48

=106 (g/mol)

Then, you find out the mass of Na2CO3 needed to give .025 mol (the amount of moles in the solution)

moles= mass / molar mass

Therefore, mass = moles X molar mass

=0.025 x 106

2.65g

Hope this helps !!!☺️

Answer 2

Answer:

Let X be the amount of na2co3

Explanation: