Question

How many grams of Na2co3 should be dissolved to make 100cm3 of0.15M Na2co3 solution

Answer 1

Answer:

Molarity is defined as the number of moles present in a liter of solution.

Mathematically,         Molarity = \frac{no. of moles}{Volume}Volumeno.ofmoles

It is given that molarity is 0.15 M and volume is 100 cc which is also equal to 0.1 liter.

Molar mass of Na_{2}CO_{3}Na2CO3 is 106 g/mol.

Therefore, calculate number of moles as follows.

             Molarity = \frac{no. of moles}{Volume}Volumeno.ofmoles

        No. of moles = Molarity \times volumeMolarity×volume

                              = 0.15 M \times 0.1 L0.15M×0.1L

                              = 0.015 mol

Now, calculate the mass in grams as follows.

          No. of moles = \frac{mass}{Molar mass}Molarmassmass  

                       Mass = no. of moles \times molar mass of Na_{2}CO_{3}no.ofmoles×molarmassofNa2CO3

                                 = 0.015 mol \times 106 g/mol0.015mol×106g/mol

                                 = 1.59 g

Thus, we can conclude that there will be 1.59 grams of Na_{2}CO_{3}Na2CO3 should be dissolved to make 100 cc of 0.15 M Na_{2}CO_{3}Na2CO3 .

Explanation:

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