how many grams of Na2CO3 will be required for preparation of 5 litre solution of 0.2 N NA2CO3?
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Answer:
53
Explanation:
N=(w/gram equivalent weight)× 1/v
0.2=(w/106/2)×1/5
0.2×5=w/53
1=w/53
W=53
NO OF GRAMS REQUIRED =53
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