How many grams of Na2SO3 are needed to prepare, five liters of 8% (w/w) solution having a density of 1.075 gm/cc. Molar mass of Na2SO3 is 126.
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of 8% (w/w) solution having a density of 1.075 gm/cc. Molar mass of Na2SO3 is 126.
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Answer:
Explanation:
The first thing that you need to do here is to use the density of the solution to determine the mass of
150 mL
of this hydrochloric acid solution.
The density of the solution is said to be equal to
1.1 g mL
−
1
, so right from the start, you know that every
1 mL
of solution will have a mass of
1.1 g
.
This means that your sample will have a mass of
150
mL
⋅
1.1 g
1
mL
=
165 g
Now, in order to find the solution's percent concentration by mass,
% m/m
, you need to figure out the mass of hydrochloric acid present in
100 g
of this solution.
Since you know that
165 g
of solution contain
30. g
of hydrochloric acid, you can say that
100 g
of this solution will contain
100
g solution
⋅
30. g HCl
165
g solution
=
18.18 g HCl
You can thus say that the solution has a percent concentration by mass equal to
% m/m = 18% HCl
−−−−−−−−−−−−−−−−−
The answer is rounded to two sig figs.