How many grams of nacl are produced when 80.0 grams of o2 are produced?
Answers
Na2O+Cl------)NaCl+O2
80grams of NaCl will also be produced
We begin with a balanced chemical equation that is provided in the question.
2NaClO3→2NaCl + 3O2
Next we determine what we have and what we want.
We have 80.0 grams of Oxygen and we want grams of Sodium Chloride.
We set up a roadmap to solve the problem
gramsO2→molO2→molNaCl→gramsNaCl
We need the molar mass (gfm) of O2 and NaCl.
O2= 31.98 g/mol and NaCl = 58.44 g/mol.
We need the mole ratio between O2:NaCl 3:2. This comes from the coefficients of the balanced chemical equation. I
Now we set up conversion factors following the roadmap from above.
Unit we want in the numerator, unit to cancel in the denominator.
80.0gO2× (1molO2/31.98gO2)×(2molNaCl/3molO2)×(58.44gNaCl/1molNaCl)= 97.5g NaCl
Multiply the numerators, and divide the denominators.
The outcome is 97.5g NaCl will be produced with 80.0 grams O2