How many grams of NaOH are needed to prepare 800 mL Of 0.8 M solution (Mw NaOH = 40.00 g / mole) ?
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Answer...
M = w x 1000/ MM x V
w = M x MM x V /1000
w = 0.8 x 40 x 800 / 1000
w = 0.8 x 4 x 8
w = 25.6 g
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