Question

How many grams of naoh are required to prepare 200 ml of a 0.450 m solution?

Answer 1

Answer:

given, Molarity of solution,M=0.450M

volume=200/1000=0.2L

then ,

M=n/V= n=MV

n=0.450*0.2=0.09 moles

now, no.of moles= required mass/molecular mass

0.09=required mass*40

required mass=0.09/40=0.00225gm