Question

How many grams of NaOH is produced from�1.20x10^2�grams of�Na2O? Na subscript2 O+H subscript2 O?2NaOH

Answer 1

Answer : The amount of NaOH produced is, 155.04 grams

Solution : Given,

Mass of $Na_2O$ = 120 g

Molar mass of $Na_2O$ = 61.9 g/mole

Molar mass of $NaOH$ = 44 g/mole

First we have to calculate the moles of $Na_2O$.

$\text{Moles of }Na_2O=\frac{\text{Mass of }Na_2O}{\text{Molar mass of }Na_2O}=\frac{120g}{61.9g/mole}=1.938moles$

Now we have to calculate the moles of NaOH.

The balanced chemical reaction will be,

$Na_2O+H_2O\rightarrow 2NaOH$

From the balanced reaction, we conclude that

1 mole of $Na_2O$ react to give 2 moles of NaOH

1.938 moles of $Na_2O$ react to give $2\times 1.938=3.876$ moles of NaOH

Now we have to calculate the mass of NaOH.

$\text{Mass of NaOH}=\text{Moles of NaOH}\times \text{Molar mass of NaOH}$

$\text{Mass of NaOH}=3.876moles\times 44g/mole=155.04g$

Therefore, the amount of NaOH produced is, 155.04 grams