Question

How many grams of naoh is required to react with 3.1 g of p4?

Answer 1

3g of NaOH is required to react with 3.1g of P4 to form PH3 and NaH2PO2.

given, mass of P4 = 3.1gram

molecular mass of P4 = 124 g/mol

then, no of moles of P4 = 3.1/124 = 1/40

= 0.025 mol

chemical reaction between p4 and NaOH is given as,

P4 + 3NaOH + 3H2O ⇒PH3 + 3NaH2PO2

here it is clear that, one mole 3 mol of NaOH reacts with 1 mol of P4.

so, 0.025 mol of P4 reacts with 3 × 0.025 = 0.075 mol of NaOH.

molecular mass of NaOH = 40 g/mol

so, mass of 0.075 mol of NaOH = 40 × 0.075 = 3g

hence, 3g of NaOH is required to react with 3.1g of P4 to form PH3 and NaH2PO2.

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