How many grams of NaOH will be needed to prepare 350 mL of 0.1 M solution
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Answer:
We know molarity is the ratio of number of moles to the volume of solution in litres.
Here, molarity is 0.1
Volume=250ml
Moles of NaOH=0.1*250/1000=1/40
Moles=Mass/Molar mass
=>Mass=1/40*40=1g
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