How many grams of neon will have the same number of atoms as 4g of calcium?
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Answered by
236
Mass of 1 atom of Ne = 20/6.022*10²³ g
Now,
Number of particles in 4 g of Ca,
= 4/40*6.022*10²³
= 6.022*10²² atoms
Therefore, number of atoms of Ne same as 4 g of Ca
= 20*6.022*10²²/6.022*10²³
=20/10
=2 g
i hope it helps..........
Answered by
78
Hope it would help you.
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