Question

How many grams of neon will have the same number of atoms as 4grams of calcium

Answer 1

Mass of 1 atom of Ne = 20/6.022*10²³ g

Now,

Number of particles in 4 g of Ca,

= 4/40*6.022*10²³

= 6.022*10²² atoms

Therefore, number of atoms of Ne same as 4 g of Ca

=

20*6.022*10²²/6.022*10²³

=20/10

=2 g

i hope it helps..........

Answer 2

Number of particles in 4 g of Ca,

= 4/40×6.022×10²³

= 6.022×10²² atoms

Therefore, number of atoms of Ne same as 4 g of Ca

= 20×6.022×10²²/6.022×10²³

=20/10

=2 g