how many grams of NH3 are produced 28.2 gram of nh4cl when reacted with Ca(OH)2. (2NH4Cl + Ca(OH)2 = NH3 + CaCl2 + 2H2O)
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Ca(OH)2 +2 NH4Cl -> CaCl2 + 2 NH3 + 2H2O. Thus 1 mole of Ca(OH)2 requires 2 moles of NH4Cl. 1.87 moles of it will react with 1.35/2= 0.675 moles of Ca(OH)2 producing 1.35 moles of NH3 i.e. 34 g × 1.35 =45.9 g of it.
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