Question

How many grams of nitric acid, HNO3, can be prepared from the reaction if 138g of NO2 according to the equation below

Answer 1

Answer:

Dhoyeryugdtutogddghjo

Answer 2

Answer:

126 g

Explanation:

Molecular weights

H → 1.008 g/mol

N → 14.01 g/mol

O → 16.00 g/mol

MW NO2 = 14.01 + 2(16.00) = 46.01 g/mol

MW H2O = 2(1.008) + 16.00 = 18.02 g/mol

MW HNO3 = 1.008 + 14.01 + 3(16.00) = 63.02 g/mol