Question

How many grams of nitrogen are needed to produce 100 grams of ammonia gas?

Answer 1

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Answer 2

The mass of nitrogen gas needed to produce given amount of ammonia is 82.32 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     .....(1)

Given mass of ammonia = 100 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

$\text{Moles of ammonia}=\frac{100g}{17g/mol}=5.88mol$

The chemical equation for the decomposition of ammonia follows:

$N_2+3H_2\rightarrow 2NH_3$

By Stoichiometry of the reaction:

2 moles of ammonia are produced by 1 mole of nitrogen gas

So, 5.88 moles of ammonia will be produced by = $\frac{1}{2}\times 5.88=2.94mol$ of nitrogen gas

Now, calculating the mass of nitrogen gas from equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 2.94 moles

Putting values in equation 1, we get:

$2.94mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(2.94mol\times 28g/mol)=82.32g$

Learn more about stoichiometry of the reaction:

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