How many grams of nitrogen gas is present in 5.6dm3 at STP
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Explanation:
Molecular weight of Nitrogen gas (N2)= 28g. And we know that, Moles = Given mass ( in grams)/ Molecular weight. So, at STP, 1 mole occupies 22.4L, so 0.25 moles will occupy: Volume= 22.4×0.25= 5.6L (ANS).
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