Question

How many grams of nitrogen is required to completely react with 54g of magnesium
to form magnesium nitride

Answer 1

Answer:

63gms of nitrogen is required.

Explanation:

by the problem, we get,

N2+Mg=MgN2.

so, Nitrogen has 2no.of moles in it & atomic mass is 14.

N2=14×2=28

magnesium contains 24 as it's atomic mass.

soo, 24gms of mg requires 28 GM's of nitrogen

54gms of mg requires =????(x)

x=28×54/24

=63gms.

Therefore,for 54gms of mg 63gms of N2 is required.....

HOPE IT HELPS YOU.....