Question

how many grams of O2 are required to exactly burn up the 114 grams of cs2

Answer 1

hey friend

CS2 + 3 O2 ---> CO2 + 2 SO2 

1 mole CS2 produces 1 mole CO2 (from equation) 

1 mole CS2 = (12.01 + 32.06 + 32.06) = 76.13 gram 

so 114 gram CS2 is 114/76.13 = 1.50 mole 

This will give 1.50 mole CO2 (see above) which weighs 1.50 x (12.01 + 16 + 16) = 66.02 gram


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